Atoms components , Rutherford and Bohr’s Atomic Models

It is known that matter is composed of atoms , These atoms show the physical and chemical properties of the matter , By the end of the nineteenth century , Scientists had become sure that electrons are from the main components of atoms .

Electrons are negatively charged particles of a very small mass , Since the atom is electrically neutral , So , the atom has other particles carrying positive charges equal to the negative charges of the electrons .

However , There wasn’t a known distribution for the positive and the negative charges in the atom at that time .

Rutherford and Bohr’s Atomic Models

According to the experiment of Rutherford in 1911 and Bohr’s theory in 1913 , the atomic structure became more acceptable .

Rutherford’s atomic models

A heavy nucleus carries a positive charge in the centre of atom , Negative electrons rotate around the nucleus at a relatively far distance , Most of the atomic volume is space .

The nucleus’s diameter = 10−610−5 nm , while the atom’s diameter = 1 × 10−10 m ( 0.1 nm ) , The mass of the atom is concentrated in the nucleus .

Bohr's Atomic Models

Bohr’s Atomic Models

Bohr’s atomic models

The negatively charged electrons rotate around the nucleus in certain fixed orbits called energy levels , Each energy level is occupied by a certain number of electrons that can’t be increased .

Discovery of proton 

Rutherford proved in 1919 that the nucleus of atom contains positively charged particles called protons , where the mass of proton is larger than that of the electron by 1800 times approximately .

Discovery of neutrons

Nevil Sidgwick discovered in 1932 that the nucleus contains particles that neutrally charged called neutrons , where the mass of neutron is nearly similar to the mass of proton .

The atom’s mass is concentrated in the nucleus because the mass of electrons is too small ( negligible ) compared to the mass of protons and neutrons ( mass of protons = 1800 times of electron mass ) .

The atom is electrically neutral because the number of positive charged protons in the nucleus equals to the number of negative charged electrons rotating around the nucleus .

Mass number and Atomic number

To describe the nucleus of the atom of any element , you should know Mass number ( A ) , Atomic number ( Z ) and Neutrons number ( N ) .

Mass number ( A ) is the sum of the numbers of protons and nucleus of the element atom .

Atomic number ( Z ) is the number of protons inside the nucleus of the element atom , Number of protons = Number of electrons .

Neutrons number N , N = A – Z .

Nucleons are the protons and neutrons inside the nucleus .


Isotopes are the atoms of the same element that have the same atomic number ( Z ) , but differ in mass number ( A ) due to the difference in the number of neutrons inside their nuclei .

The isotopes have the same chemical properties because they have similar number of electrons and the same electron configuration around the nucleus , Most elements in the periodic table have more than one isotope .

Hydrogen isotopes

Hydrogen is the simplest element in the nature , It has three isotopes , Name of isotopes are Protium , Deuterium and Tritium .

The atomic number equals the mass number in protium nucleus because it does not contain neutrons .

Number of neutrons equals the number of protons in deuterium nucleus , while it equals double the number of protons in tritium nucleus .

Oxygen isotopes :

Oxygen element has three isotopes which are Oxygen-18 , ‏Oxygen-16 , ‏Oxygen-17 .

In nuclear chemistry , other nuclear terminology is used in addition to the isotopes , which are :

Isobars : They are the nuclei of atoms of different elements that have the same number of mass ( A ) , but they differ in the atomic number ( Z ) .

Isotones : They are the nuclei of atoms of different elements that have the same number of neutrons , but they differ in the mass number .

Atomic mass units amu ( u )

Masses of atomic isotopes are too small , So , They are measured in atomic mass units amu or u = 1.66 × 10−24 g = 1.66 × 10−27 kg 

Atomic masses of elements can be identified by knowing the relatively atomic masses of their isotopes and the ratio of the presence of each of them .

Relationship between mass and energy

Calculation of the produced energy from the transforming of a mass of a substance ( estimated in kilograms kg ) to energy ( estimated in Joule J ) .

E = m . c²

E = Energy ( J ) , m = transformed mass ( kg ) , c = light speed ( 3 × 108 m/s )² .

Calculation of the produced energy from the transforming of a mass of a substance ( estimated in atomic mass unit u ) to energy ( estimated in million electron volt unit MeV ) .

E = m × 931

E = Energy ( Me V ) , m = Mass ( u ) , 931 = constant value .

Properties of Strong nuclear forces , Source of nuclear binding energy and Quark Model

Evolution concept of the atomic structure , Atomic theory & Properties of cathode rays

Atomic emission spectra , Bohr’s atomic theory , Wave mechanical theory of the atom

You may also like...

Leave a Reply

Your email address will not be published. Required fields are marked *